Answer to Question #90821 in Atomic and Nuclear Physics for Arinze

Question

Find the average velocity of the equation
x=t²+2t+3 when t=0, t=5

Answer 1

By definition, the average velocity is just a ratio of a distance travelled to the time it takes to travel this distance:

$$\lt v \gt =\frac{x(t_2)-x(t_1)}{t_2 - t_1}$$

In the given system of units (no dimension is specified) we have:

$$t_2 = 5, \quad t_1 = 0\\ x(t_2) = 25 + 10 + 3 = 38, \quad x(t_1) = 3$$

Hence, we obtain:

$$\lt v \gt =\frac{38-3}{5} = 7$$

Answer: 7