Answer to Question #88621 in Atomic and Nuclear Physics for Sridhar

Question

a beta particle of energy 1MeV enters a thin window detector tube filled with methane and organ and initiates an avalanche of 5×10^10 Ion pairs the average energy lose per ion pair creation is 50 eV. the multiplication factor is

Answer 1

the multiplication factor is equal to

$$\frac {50 \times 10^{10} \times 50} {1\times 10^6} =2.5 \times 10^7$$

Answer:

$2.5 \times 10^7$