Answer to Question #87536 in Atomic and Nuclear Physics for Shivam Nishad

Question

Define binding energy. Calculate the binding energy per nucleon of Fe. Given
( Fe) = 55.934932u, Mn= 1.008665u and Mp= 1.007825 u.

Answer 1

Mass defect:

$$Δm=Zm_p+(A-Z)m_n-m(Fe) (1)$$

where Z=26, A=56

Using (1) we got: Δm=0.5285 u

Binding energy W

1 u – 931.5 MeV

0.5285 u – W

W=492.3 MeV

The binding energy per nucleon:

$$w=\frac {W}{A} (2)$$

Using (2) we got:

w=8.79 MeV/nucleon

Answer:

Binding energy: 492.3 MeV

binding energy per nucleon: 8.79 MeV/nucleon