Answer to Question #74663 in Atomic and Nuclear Physics for Hagar salah

Question

A body is left free at height h= 19.6m ( with initial velocity v0= 0 ) . What is the path covered by the body . 1) in initial time interval t1 = 0.1 s
2) and during the time period t2 = 0.1 s just before striking the ground ?

Answer 1

1) The path covered by the body is S_1=(gt_1^2)/2=(9.8⋅〖0.1〗^2)/2=0.049m.
2) Time of falling is t_0=√(2h/g)=√((2⋅19.6)/9.8)=2s.
The path covered by the body is S_2=h-(g(t_0-t_2 )^2)/2=19.6-(9.8⋅〖1.9〗^2)/2=1.911m.
Answer: S_1=0.049m,S_2=1.911m.