I was curious about a radioactive decay battery. My thought was to place an americium source from a smoke detector in a vacuum sealed borosilicate glass vessel. The Americium source would be "aimed" at a piece of Titanium 2 mm's away.
The vacuum sealed glass vessel would have 2 wires coming out of it. 1 wire would be attached to the Source. 1 would be attached to the Titanium.
As I understand it, the current of such a device would be in the nanoamp range (2 or 3). I was very curious what the voltage would be?
I understand that the answer would be approximite, but I was still curious. Would it be closer to 5 Volts? or 50,000 Volts?
Thank You, Paul