Answer to Question #71520 in Astronomy | Astrophysics for Josefina

Astronomy | Astrophysics

Question #71520

A rock dropped into a well is heard to splash 2.30 seconds later. How deep is the well to the water's surface?

Expert's answer

s=(gt^2)/2=1/2×9.81 m/s^2 × 2.30 s^2≈11.28 m

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