Answer to Question #64818 in Astronomy | Astrophysics for Ahmed

Question

A skydiver with a mass of 68.96 kg dives out of a perfectly good airplane and plummets toward the Earth below. After falling for several seconds, the diver's acceleration is measured at 4.05 m/s2. What is the magnitude of the force of air resistance at this moment?

Answer 1

ma=mg-F_res,
F_res=m (g-a)=68.96 (9.8-4.05)=396.52 N