# Answer to Question #36934 in Astronomy | Astrophysics for raashee

Question #36934

what is the value of g on the surface of a planet whose mass as well as radius is half of the value for earth

Expert's answer

by definition

g=G*M/R^2 ( G- gravitation constant, M- mass of the planet, R- radius of the planet)

since M1=M/2

and R1=R/2

the g1=g*2

so, new "g" will be 2 times LARGE then original one

if the original g=9.81m/c^2,

the new one g1=19.62m/c^2

g=G*M/R^2 ( G- gravitation constant, M- mass of the planet, R- radius of the planet)

since M1=M/2

and R1=R/2

the g1=g*2

so, new "g" will be 2 times LARGE then original one

if the original g=9.81m/c^2,

the new one g1=19.62m/c^2

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