Answer to Question #27859 in Astronomy | Astrophysics for SHANICE
F = G*m*M/r^2
where m is mass of body and M is mass of mercury, r is distance to the center (radius), G is gravitational constant.
Then the acceleration is
a=F/m =& G*M/r^2 = 6.67 x 10^(-11) x 2.99 x 10^(23) /( 2.42 x 10^6)^2 = 3.4 m/s^2
So, the magnitude of the acceleration due to gravity on planet mercury is 3.4 m/s^2
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