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Answer to Question #16197 in Astronomy | Astrophysics for NDwing
Question #16197
A robot probe lands on a new, uncharted planet. It has determined the diameter of the planet to be 8 * 10^6 m. It weighs a standard 1 kg mass and determines the 1 kg weighs only 5 newtons on this new planet.
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R = 8*10^6 m m = 1 kg P = 5 N Gravity law: P = mg = GM/R^2, where g is the acceleration of the gravity, M is the mass of the planet, G=6.67*10^-11 m^3/(kg*s^2) is the gravitational constant. Thus, g = P/m = 5 m/s^2, M = gR^2/G = 4.8*10^24 kg. Average density is rho = M/V, where V = 4/3*pi*R^3 is the volume of the planet. rho = 3g/(4*pi*G*R) = 2200 kg/m^2.
who can tell me the mass, acceleration of gravity,and avg. density in this situation?
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