According to the third Kepler's law,
"\\displaystyle (m+M) P^2 = a^3 \\; \\; \\Rightarrow \\; \\; m+M = \\frac{a^3}{P^2} = \\frac{10^3}{5^2} =\\frac{1000}{25} = 40" solar masses.
Answer: 40 solar masses.
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