Answer to Question #1871 in Acoustics for nirmala
<br>(ii) after the engine passes the observer. <br>The speed of sound in air is 340 m/s.
f = (Vsound / (Vsound +Vsource)) f0
72 km/h = 20 m/s
(i) before: Vsource is positive
f = (340/(340 - 20))*500 = 531.25 Hz
(ii) after: Vsource is negative
f = (340/(340+20))*500 = 472.22 Hz
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