Question #1588

a stone is dropped from a cliff onto a flowing river below. if it takes the stone 0.185 minutes to hit the water, how high is the cliff?

Expert's answer

According to the equations of the motion,

h = h_{0} + v_{0}t - gt^{2}/2

In our case h =0, v_{0}= 0, t = 0.185[minutes] *60 = 11.1 [s], g= 9.8 [m/s^{2}]

thus

h_{0} = gt^{2}/2 = 9.8* 11.1^{2}/2 = 603.729 [m]

h = h

In our case h =0, v

thus

h

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