# Answer to Question #9916 in Trigonometry for Eliana Hernandez

Question #9916

solve on the interval [0, 2pi).

1.2sin^2(x)+cos(x)=1

2.cos(x)=-0.8092

3.tan(x)sec(x)=3tan(x)

1.2sin^2(x)+cos(x)=1

2.cos(x)=-0.8092

3.tan(x)sec(x)=3tan(x)

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