Answer to Question #75684 in Trigonometry for Bridget

Question #75684
Directions: show the steps that leads to the answers

For each problem, determine the values of x such that 0 ≤ x < 2π that satisfy equation.

(1) Solve sin x cos x = 0. (Answers: x = 0, π/2, π, 3π/2)

(2) Solve 2 sin2 x − sin x − 1 = 0. (Answers: x = π/2, 7π/6, 11π/6)

(3) Solve cos x + cos 2x = 0. (Answers: x =π/3, π, 5π/3)

(4) Solve 2 cos x + sec x = 3. (Answers: x = 0, π/3, 5π/3)

(5) Solve sec x − 1 = tan x. (Answer: x = 0)
1
Expert's answer
2018-04-06T17:54:35-0400
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