Question #5035

if secx,0and cotx,0,in which quadrant does the terminal side of the angle x lie?

Expert's answer

Dear Maureen

the question is not clear. Did you mean secx>0and cotx>0& ? If so then take a look at the solution

we know that sec x=1/cosx>0 hence cos x>0 => it's 1 or 4 quadrant

cot x=sin x/ cos x>0 => sin x>o (because we've already known that cos >0) hence it's 1 quadrant

the question is not clear. Did you mean secx>0and cotx>0& ? If so then take a look at the solution

we know that sec x=1/cosx>0 hence cos x>0 => it's 1 or 4 quadrant

cot x=sin x/ cos x>0 => sin x>o (because we've already known that cos >0) hence it's 1 quadrant

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