Answer to Question #5035 in Trigonometry for maureen
if secx,0and cotx,0,in which quadrant does the terminal side of the angle x lie?
Dear Maureen the question is not clear. Did you mean secx>0and cotx>0& ? If so then take a look at the solution we know that sec x=1/cosx>0 hence cos x>0 => it's 1 or 4 quadrant cot x=sin x/ cos x>0 => sin x>o (because we've already known that cos >0) hence it's 1 quadrant