Answer to Question #4964 in Trigonometry for BLAKE

Question

find the exact value of cos and sin of angle (3, -6)

Answer 1

Please give us details so we could help you.Should we understand that it's angle created by the line which goes through origin and contains point (3,-6)? Like on the picture below? if so
then cos = 3/sqrt(9+36)=3/(3*sqrt(5))=1/sqrt(5)
sin=-6/sqrt(9+36)=-6/(3*sqrt(5))=-2/sqrt(5)

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