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Answer to Question #4684 in Trigonometry for Deepu K Sam

Question #4684
Elevation of a tower at a Station A due north of it is x and at a Station B due wist of A is y. Prove that height or the tower is AB*(sin(x)*sin(y))/sqrt(sin^2(x)-sin^2(y))
Expert's answer
Unfortunately it's not clear from the question what are x and y.

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