# Answer to Question #4615 in Trigonometry for pratyush

Question #4615

if cot b =12/5,then proof tan^2 b-sin^2b=sin^4b sec^b

Expert's answer

cot b=12/5

tan^2 b – sin^2 b=sin^4 b * sec^4 b

sec^4 b = 1/cos^4 b

tan^2 b – sin ^2 b= tan^4 b

1/cot^2 b – sin ^2 b= 1/cot^4 b

sin^2 b=25/144-625/20736=2975/20736

625/20736=625/20736

tan^2 b – sin^2 b=sin^4 b * sec^4 b

sec^4 b = 1/cos^4 b

tan^2 b – sin ^2 b= tan^4 b

1/cot^2 b – sin ^2 b= 1/cot^4 b

sin^2 b=25/144-625/20736=2975/20736

625/20736=625/20736

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