Question #3009

Find sin(2θ) Use the fact that cos(θ)=1/6 and 0°≤θ≤90°

Expert's answer

As sin(2θ) = 2 sinθ cosθ, and sinθ = √(1-cos^{2}θ) =√(1 - 1/36) = √(35/36) = √35/6,

sin(2θ) = 2 * 1/6 * √35/6 = √35/18

sin(2θ) = 2 * 1/6 * √35/6 = √35/18

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