# Answer to Question #22480 in Trigonometry for Kristen Woods

Question #22480

Solve the given equations by factoring.

5a. x^2-14=5x

5b. 6x^2+7x+2=0

5a. x^2-14=5x

5b. 6x^2+7x+2=0

Expert's answer

5a. x^2-14=5xx^2-5x-14=0

x^2-7x+2x-14=0

x(x-7)+2(x-7)=0

(x+2)(x-7)=0

so x1=-2, x2=7

5b. 6x^2+7x+2=06x^2+3x+4x+2=0

3x(2x+1)+2(2x+1)=0

(3x+2)(2x+1)=0

x=-2/3, x=-1/2

x^2-7x+2x-14=0

x(x-7)+2(x-7)=0

(x+2)(x-7)=0

so x1=-2, x2=7

5b. 6x^2+7x+2=06x^2+3x+4x+2=0

3x(2x+1)+2(2x+1)=0

(3x+2)(2x+1)=0

x=-2/3, x=-1/2

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