82 271
Assignments Done
98,6%
Successfully Done
In January 2020

# Answer to Question #22415 in Trigonometry for Brenden Fields

Question #22415
Solve, write your answer in interval notation and graph the solution set. 14c. |2x-1| + 7 greater than or equal to 1 14d. |5x+3| less than or equal to -1
1
2013-01-21T09:31:13-0500
14a. |5y-2| < 13
-13 < 5y -2 < 13
-13+2 < 5y < 13+2
-11 < 5y < 15
-11/5 < y < 15/5
-2.2 < y < 3

So y in (-2.2, 3)

-------------------o=============================o-------------------->
-2.2 3
the ends are notincluded, and the solution is shown with====

14b. |x+1|>= 5

Consider two cases:

1) x+1<0.Then |x+1|=-x-1, and so we have the inequality

-x-1 >=5
-x >=5+1=6
x <= -6
x in(-infinity, -6]

1) x+1>=0.Then |x+1|=x+1, and so we have the inequality

x+1 >= 5
x >=5-1=4
x >= 4
x in [4,+infinity)

Thus the solution has the following form:
y in (-infinity, -6] U [4, +infinity)

Answer: (-infinity, -6] U [4, +infinity)

================*---------------------*==============================>
-6 4
the ends are included, and the solution is shown with====

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!