# Answer to Question #19646 in Trigonometry for mike

Question #19646

solve the equation for the interval [0,2pi)

sin2X + sin X = 0

sin2X + sin X = 0

Expert's answer

sin2X+ sin X = 0

2sinX cosX + sin X = 0

sin X(2cos X +1 ) = 0

several solutions

sin X = 0

X = 0, Pi

2cos X = -1

cos X = -1/2

X = 2/3 Pi, 7/6Pi

2sinX cosX + sin X = 0

sin X(2cos X +1 ) = 0

several solutions

sin X = 0

X = 0, Pi

2cos X = -1

cos X = -1/2

X = 2/3 Pi, 7/6Pi

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