# Answer to Question #19578 in Trigonometry for Kristen Woods

Question #19578

solve and write in standard form

1a. 5+(2+3i)+(-3-7i)

1b. (5-10i)-(2+i)

1c. -5i(2-3i)

1d. (2+3i)(-3-7i)

1e. 2+4i/3-i

1f. 3 square root of -50 + square root of -72

1g. (7-square root of -15)^2

1h. -4+square root of -20 / 2

1i. 7 square root of -2 (-4 square root of -3)

1a. 5+(2+3i)+(-3-7i)

1b. (5-10i)-(2+i)

1c. -5i(2-3i)

1d. (2+3i)(-3-7i)

1e. 2+4i/3-i

1f. 3 square root of -50 + square root of -72

1g. (7-square root of -15)^2

1h. -4+square root of -20 / 2

1i. 7 square root of -2 (-4 square root of -3)

Expert's answer

1a. 5+(2+3i)+(-3-7i)

4-4i

1b. (5-10i)-(2+i)

3-11i

1c. -5i(2-3i)

-15-10i

1d. (2+3i)(-3-7i)

15-23i

1e. 2+4i/3-i

2+i/3

1f. 3 square root of -50 + square root of -72

-3.684+8.485i

1g. (7-square root of -15)^2

2.168

1h. -4+square root of -20 / 2

-4+3.162i

1i. 7 square root of -2 (-4 square root of -3)

1.002+0.351i

4-4i

1b. (5-10i)-(2+i)

3-11i

1c. -5i(2-3i)

-15-10i

1d. (2+3i)(-3-7i)

15-23i

1e. 2+4i/3-i

2+i/3

1f. 3 square root of -50 + square root of -72

-3.684+8.485i

1g. (7-square root of -15)^2

2.168

1h. -4+square root of -20 / 2

-4+3.162i

1i. 7 square root of -2 (-4 square root of -3)

1.002+0.351i

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