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# Answer to Question #1755 in Trigonometry for Isha

Question #1755
Solve this trigonometric equation.give all positive values of the angle between 0deg and 360deg that will satisfy.&lt;br&gt;Give any approximate value to the nearest minute only.

&lt;br&gt;& tan (x+15) = 3 tanx
1
2011-03-03T08:26:11-0500
tan(x+15) = (tanx + tan15)/(1-tanx tan15)
(tanx + tan15)/(1-tanx tan15) = 3 tanx
tanx + tan 15 = 3 tanx - 3tan2x tan15
3 tan2x tan15 - 2tanx + tan15 = 0
tan15 = 0.27, denote tanx as t
0.81 t2 - 2t + 0.27 = 0
D = 0.1252
t1 = 1.67
t2 = 0.80
tan (x1) = 1.67
x1 = arctan (1.67) + &pi;n = 59.087 + 180n = 59&ordm; 5&#039;+ 180n, n=0,1,2,..
tan(x2) = 0.80
x2 = arctan(0.80) + &pi;n = 38.66 + 180n = 38&ordm; 40&#039; + 180n, n=0,1,2,..

Answer: 59&ordm; 5&#039;, 239&ordm; 5&#039;, 38&ordm; 40&#039;, 218&ordm; 40&#039;

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