# Answer to Question #17508 in Trigonometry for Vladimir Bautista

Question #17508

Find an algebraic expression for sin[arccos(3x)]. PLEASE show the steps

Expert's answer

sin( t )=sqrt(1-cos^2 ( t ) )

sin(arccos(3x))=sqrt(1-cos^2 (arccos(3x)))=sqrt(1-(3x)^2)=sqrt(1-9x^2)

sin(arccos(3x))=sqrt(1-cos^2 (arccos(3x)))=sqrt(1-(3x)^2)=sqrt(1-9x^2)

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