Question #16697

cos(x)^(4)-sin(x)^(4)=2cos(x)^(2)-1

Expert's answer

cos(x)^(4)-sin(x)^(4)=(cos(x)^(2)-sin(x)^(2)

)*(cos(x)^(2)+sin(x)^(2))= =cos(x)^(2)-sin(x)^(2)=cos(x)^(2)-(1cos(x)^(2))=2cos(x)^(2)-1

we

use here cos(x)^2+sin(x)^2=1

)*(cos(x)^(2)+sin(x)^(2))= =cos(x)^(2)-sin(x)^(2)=cos(x)^(2)-(1cos(x)^(2))=2cos(x)^(2)-1

we

use here cos(x)^2+sin(x)^2=1

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