Answer to Question #15042 in Trigonometry for shubham
D = 30[km/h] * 10[s] = 30[km/h] * 1/360[h] = 1/12 [km].
So, the angle it has turned is
& alpha; = D/R = (1/12[km])/(0.750[km]) = 1/9 rad.
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