Answer to Question #127319 in Trigonometry for zakiaa

Question

sin 60 cos30 cos60 sin30 sin30 o o o o o

Answer 1

Let X = $\sin 60\degree * \cos 30\degree * \cos 60\degree * \sin 30\degree * \sin 30\degree$

$\sin 60\degree = \sqrt{3}/2$

$\cos 30\degree = \sqrt{3}/2$

$\cos 60\degree = 1/2$

$\sin 30\degree = 1/2$

So substituting the above values in X

$\therefore$ X = $\sqrt{3}/2$ * $\sqrt{3}/2$ * $0.5$ * $0.5$ * $0.5$

= 3/32