# Answer to Question #8173 in Statistics and Probability for BAM MacDaniels

Question #8173

If I have 5 ten sided dice, what is the probability that all of them will show numbers 1-7? What about only 4? What about only 3, or 2, or 1, or none?

Expert's answer

For 5 ten sided dice the probability that all of them will show numbers 1-7 is

(7/10)^5=16.81%

For 5 ten sided dice the probability that only 4 of them will

show numbers 1-7 is (3/10)* (7/10)^4=7.20%

For 5 ten sided dice the

probability that only 3 of them will show numbers 1-7

is((3/10)^2)*(7/10)^3=3.01%

For 5 ten sided dice the probability that only 2

of them will show numbers 1-7 is ((3/10)^3)*(7/10)^2=1.32%

For 5 ten sided

dice the probability that only 1 of them will show numbers 1-7 is

(7/10)*(3/10)^4=0.57%

For 5 ten sided dice the probability that none of them

will show numbers 1-7 is (3/10)^5=0.24%

(7/10)^5=16.81%

For 5 ten sided dice the probability that only 4 of them will

show numbers 1-7 is (3/10)* (7/10)^4=7.20%

For 5 ten sided dice the

probability that only 3 of them will show numbers 1-7

is((3/10)^2)*(7/10)^3=3.01%

For 5 ten sided dice the probability that only 2

of them will show numbers 1-7 is ((3/10)^3)*(7/10)^2=1.32%

For 5 ten sided

dice the probability that only 1 of them will show numbers 1-7 is

(7/10)*(3/10)^4=0.57%

For 5 ten sided dice the probability that none of them

will show numbers 1-7 is (3/10)^5=0.24%

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