# Answer to Question #7132 in Statistics and Probability for Annie

Question #7132
A supermarket polled 1,000 customers regarding the size of their bill. The results are given in the table below. Size of Bill Number of Customers below \$20.00 203 \$20.00–\$39.99 117 \$40.00–\$59.99 182 \$60.00–\$79.99 176 \$80.00–\$99.99 193 \$100.00 or above 129 Use probability rules (when appropriate) to find the relative frequency with which a customer's bill is as stated. (Enter your answers as fractions.) (a) between \$20.00 and \$79.99 (b) not between \$20.00 and \$79.99
The total number of customers is N = 1000.

(a) between \$20.00 and \$79.99

The number of customers with the bill size between \$20.00 and \$79.99 is n = 117+182+176 = 475. So, relative frequency is F1 = n/N = 475/1000 = 19/40.
&
(b) not between \$20.00 and \$79.99

The number of customers with the bill size not between \$20.00 and \$79.99 is m = N-n = 1000-475 = 525. So, relative frequency is F1 = m/N = 525/1000 = 21/40.

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