55 693
Assignments Done
97,4%
Successfully Done
In November 2017
Your physics homework can be a real challenge, and the due date can be really close — feel free to use our assistance and get the desired result.
Be sure that math assignments completed by our experts will be error-free and done according to your instructions specified in the submitted order form.
Our experts will gladly share their knowledge and help you with programming homework. Keep up with the world’s newest programming trends.

Answer on Statistics and Probability Question for Misael

Question #6887
The probability that a married man watches a certain television show is 0.4 and the probability that a married woman watches the show is 0.5. The probability that a man watches the show, given that his wife does, is 0.7. Find the probability that
a) a married couple watches the show
b) a wife watches the show given that her husband does;
c) at least 1 person of a married couple will watch the show.
Expert's answer
a) a married couple watches the show

P(man|woman)=[P(man AND woman)]/[P(woman)]
Therefore (man AND woman) = P(man|woman)*P(woman) = 0.7*0.5 = 0.35.

b) a wife watches the show given that her husband does:

P(woman|man) = P(man AND woman)/P(man) = 0.35/0.4 = 0.8750

c) at least 1 person of a married couple will watch the show.



Need to figure out
P(both watch) = 0.35
P(man watches and woman does not) =P(man watches) - P(both watch)=0.40-0.35 = 0.05
P(woman watches and man does not) =P(woman watches) - P(both watch)= 0.50-0.35 = 0.15
P(at least 1 person of a couple will watch) =P(man watches and woman does not)+ P(woman watches and man does not)+P(both watch)=0.05+0.15+0.35 = 0.55

Therefore P(at least 1 person of a couple will watch)= 0.55.

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

Assignment Expert
03.09.2014 13:56

Dear John.
 Thank you for correcting us. You have used another formula for probability of union of two events. Our solution applies formula for probability of union of two mutually exclusive events.

John
01.09.2014 17:36

Hi, I think c) is not right. 0.55 is the probability that at least one person watch the program (man, woman or both). Also you can write this like this: P(man or woman)= P(man)+P(woman)-P(both)= 0.4+0.5-0.35=0.55

Leave a comment

Ask Your question