107 725
Assignments Done
100%
Successfully Done
In April 2024
In April 2024
Your physics assignments can be a real challenge, and the due date can be really close — feel free to use our assistance and get the desired result.
Physics
Be sure that math assignments completed by our experts will be error-free and done according to your instructions specified in the submitted order form.
Math
Our experts will gladly share their knowledge and help you with programming projects. Keep up with the world’s newest programming trends.
Programming
Answer to Question #6887 in Statistics and Probability for Misael
Question #6887
The probability that a married man watches a certain television show is 0.4 and the probability that a married woman watches the show is 0.5. The probability that a man watches the show, given that his wife does, is 0.7. Find the probability that
a) a married couple watches the show
b) a wife watches the show given that her husband does;
c) at least 1 person of a married couple will watch the show.
a) a married couple watches the show
b) a wife watches the show given that her husband does;
c) at least 1 person of a married couple will watch the show.
Expert's answer
a) a married couple watches the show
P(man|woman)=[P(man AND woman)]/[P(woman)]
Therefore (man AND woman) = P(man|woman)*P(woman) = 0.7*0.5 = 0.35.
b) a wife watches the show given that her husband does:
P(woman|man) = P(man AND woman)/P(man) = 0.35/0.4 = 0.8750
c) at least 1 person of a married couple will watch the show.
Need to figure out
P(both watch) = 0.35
P(man watches and woman does not) =P(man watches) - P(both watch)=0.40-0.35 = 0.05
P(woman watches and man does not) =P(woman watches) - P(both watch)= 0.50-0.35 = 0.15
P(at least 1 person of a couple will watch) =P(man watches and woman does not)+ P(woman watches and man does not)+P(both watch)=0.05+0.15+0.35 = 0.55
Therefore P(at least 1 person of a couple will watch)= 0.55.
P(man|woman)=[P(man AND woman)]/[P(woman)]
Therefore (man AND woman) = P(man|woman)*P(woman) = 0.7*0.5 = 0.35.
b) a wife watches the show given that her husband does:
P(woman|man) = P(man AND woman)/P(man) = 0.35/0.4 = 0.8750
c) at least 1 person of a married couple will watch the show.
Need to figure out
P(both watch) = 0.35
P(man watches and woman does not) =P(man watches) - P(both watch)=0.40-0.35 = 0.05
P(woman watches and man does not) =P(woman watches) - P(both watch)= 0.50-0.35 = 0.15
P(at least 1 person of a couple will watch) =P(man watches and woman does not)+ P(woman watches and man does not)+P(both watch)=0.05+0.15+0.35 = 0.55
Therefore P(at least 1 person of a couple will watch)= 0.55.
Learn more about our help with Assignments: Statistics and Probability
Comments
Dear Ahmed, You are welcome. We are glad to be helpful. If you liked our service, please press a like-button beside the answer field. Thank you!
Thanks c was very helpful
Dear Md.Mostafijur Rahman, please use the panel for submitting new questions
Convert (65983)d this decimal number to hexagonal number
Dear visitor, please use the panel for submitting new questions
Dear Mr. John i have an extra question: d) Find the probability that at most one member of a married couple will watch the show.
Dear John. Thank you for correcting us. You have used another formula for probability of union of two events. Our solution applies formula for probability of union of two mutually exclusive events.
Hi, I think c) is not right. 0.55 is the probability that at least one person watch the program (man, woman or both). Also you can write this like this: P(man or woman)= P(man)+P(woman)-P(both)= 0.4+0.5-0.35=0.55
Leave a comment