Question #6786

In a store, an average of 10 customers enters per hour. What is the probability that at most 80 customers enter the store during a 10 hour day?

Expert's answer

The random variable X of the number of customers during 10 hours has the

Poisson

distribution with E(X) = 100, (lambda = 100).

P(X <= 80) =

p0+p1+...+p80 = 0.0226492,

where pk = lambda^k * exp(-lambda) / k!

Poisson

distribution with E(X) = 100, (lambda = 100).

P(X <= 80) =

p0+p1+...+p80 = 0.0226492,

where pk = lambda^k * exp(-lambda) / k!

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