Answer to Question #5942 in Statistics and Probability for moe dawn
null hypothesis that dancing does not cause rain. If the probability of it raining on a given day is 25% (irrespective of any dancing), how many successive days of rain would be needed to be able to reject the null hypothesis at a 0.01 level of significance, and thus convince that it is wrong?
how many successive days of rain would be need at a 0.05 sig level to be able to reject the null hypothesis?
Let N be a number of successive days of rain. We can find N using chi-squared test. Number of degrees of freedom equals 1 and corresponding values in a table for chi-square distribution (for 0.01 and 0.05 levels) are 6.64 and 3.84 . Chi-squared statistics equals 3N and 3N>6.64 or 3N>3.84 to reject null hypothesis. So we need 3 or more successive days of rain to reject the null hypothesis at level 0.01 and 2 or more successive days to reject it at level 0.05.