Answer to Question #475 in Statistics and Probability for Andrew
Here is an example of 100 bobs with the weights a1, a2, … , a100 for which all numbers from 2 to 98 (97 numbers in total) are means. Let a1 = a2 = 1, a(n+2) = an + a(n+1), n = 1, 2, … , 97, – serial numbers of Fibonacci and S = a1 + a2 + ⋯ + a98. Select a100 = S − a99. Then the total weight of all bobs is 2S and also a100 + a99 = a100 + a98 + a97 = a100 + a98 + a96 + a95 = ⋯ = a100 + a98 + a96 + a94 + a92 + ⋯ + a6 + a4 + a2 + a1 = S
Therefore, the numbers 2, 3, 4, ..., 51 are means. But then the numbers 100–2=98, 100–3 =97, … , 100–48=52 are also means, i.e. all numbers from 2 to 98 are means.
Answer. 97 means
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