# Answer to Question #4582 in Statistics and Probability for KHALID JUTT

Question #4582

From a group of 4 men and 5 women, how many committees of size 3 are possible (a) with no restrictions? (b) with 1

man and 2 women? (c) with 2 men and 1 woman if a certain man must be on the committee?

man and 2 women? (c) with 2 men and 1 woman if a certain man must be on the committee?

Expert's answer

a) We choose 3 persons from 9, so there are 9!/(3!*(9-3)!) = 84 different committees.

b) We choose 1 man from 4 and 2 women from 5, so there are 4*5!/(2!*(5-2)!) = 40.

c) As a certain man is already chosen, we need to choose 1 man from 3 and 1 woman from 5, so 3*5 = 15.

b) We choose 1 man from 4 and 2 women from 5, so there are 4*5!/(2!*(5-2)!) = 40.

c) As a certain man is already chosen, we need to choose 1 man from 3 and 1 woman from 5, so 3*5 = 15.

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## Comments

Assignment Expert05.08.14, 18:42Dear dungo 1211.

Thank you for correcting us.

dungo121101.08.14, 22:07c) 1*3*5=15

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