Answer to Question #379 in Statistics and Probability for Elizabeth

Question #379
There are 90 good and 10 defective screws in the box. What is the probability that there are no defective screws among 10 randomly taken screws?
1
Expert's answer
2010-07-07T04:55:09-0400

The total amount of screws in the box is: 90+10 = 100.
The number of ways to select 10 screws from 100 is: N = (C100)^10.
The number of ways to select 10 screws from good ones is: m = (C90)^10.
Thus, the probability of taking 10 good screws is: P = m/N = ((C90)^10)/((C100)^10) = (90!*90!)/(80!*100!) ≈ 0.33

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be first!

Leave a comment

Ask Your question

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS
paypal