Answer on Statistics and Probability Question for Dong-Sun
1 – the first given question is one of 24 he knows. The probability to get it is: P(1) = 24/30 = 0.8;
2 – the first given question is one of 6 he doesn’t know, but the second one is one of 24 he knows (note that there are 29 questions left). The probability to get them is: P(2) = 6/30 * 24/29 ≈ 0.17.
As these events are independent, the probability to pass the exam is: P = P(1) + P(2) ≈ 0.8 + 0.17 ≈ 0.97.
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