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Answer to Question #35700 in Statistics and Probability for AWAIS
Question #35700
The Geometric Mean of 10 items of a series was 16,2
It was later found out that one of the items was wrongly taken as 12.9 instead of 21.9
Calculate correct GM?
kindly solve this riddle
It was later found out that one of the items was wrongly taken as 12.9 instead of 21.9
Calculate correct GM?
kindly solve this riddle
Expert's answer
The formula for geometric mean is
G = (p1*p2*p3...*pn)^(1/n)
where p1, p2,...pn are values of items
If we replace the value p_old (it is among p1, p2,...pn) with another P_new, G will change as
G' =(p_new)^(1/n)* G/((p_old)^(1/n)) =21.9^(1/10)* 16.2/(12.9^(1/10))= 17.08
G = (p1*p2*p3...*pn)^(1/n)
where p1, p2,...pn are values of items
If we replace the value p_old (it is among p1, p2,...pn) with another P_new, G will change as
G' =(p_new)^(1/n)* G/((p_old)^(1/n)) =21.9^(1/10)* 16.2/(12.9^(1/10))= 17.08
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Comments
Dear ssass. Thank you for correcting us.
BUt G=root of n (p1*p2*......Pn)
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