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Answer to Question #33988 in Statistics and Probability for rohini chandrakant chuadhari

Question #33988
if f(x)=a raise to x,a>0,show that
f(x+1)=a*f(x)=f(2)*f(x-1)
Expert's answer
We have
f(x+1)=ax+1=a*ax=a*f(x) - this is the fist equality
For the second equality we have
f(2)*f(x-1)=a2ax-1=a*(a*ax-1)=a*ax=a*f(x).
QED.

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