If six dice are rolled 100 times, how many times would you expect the number of even numbers showing to exceed the number of odd numbers showing? ANS :34 Topic: Binomial Probability

For even to exceed odd, the number of dice showing an even number must be 4, 5 or 6. The probability of getting an even number is (1/2) and odd number is (1/2).

Using the binomial probability formula: 6C4(1/2)^4 (1/2)^2 + 6C5(1/2)^5 (1/2)1 + 6C6(1/2)^6 (1/2)^0 = 11/32

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Katie06.06.15, 16:48For even to exceed odd, the number of dice showing an even number must be 4, 5 or 6.

The probability of getting an even number is (1/2) and odd number is (1/2).

Using the binomial probability formula:

6C4(1/2)^4 (1/2)^2 + 6C5(1/2)^5 (1/2)1 + 6C6(1/2)^6 (1/2)^0

= 11/32

11/32 x 100 rolls = 34.375 = 34

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