Answer to Question #26805 in Statistics and Probability for lojain
Selection of two plugs is the independent process: we select the first one and then the second.
So, we have 20*19=380 variants to make a choice.
To have both defective we have 6*5=30 variants.
So the probability that both we took from the box are defective is P= (defective variants)/(all the variants)=30/380=3/38~0.08 (or 8%)
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