Answer to Question #2373 in Statistics and Probability for bx
a) Determine the height required to be in the top 10% of all 20-25 years old females.
b) A “one-size-fits all” robe is being designed that should fit 90% of 20-25 years old females; what heights constitute the middle 90% of all 20-25 years old females?
a) We have to such H that
0.1 = P(X>H) = P( Z>(H-64.1)/2.8 ) =
= 1 - F((H-64.1)/2.8)
F((H-64.1)/2.8) = 0.9
Then, using known values of F we obtain that
H =1.281552 * 2.8 + 64.1 = 67.69
b) We have to find D such that
P(64.1-D < X < 64.1+D ) = 0.9
P(64.1-D < X < 64.1+D )& =
= P(-D/2.8 < Z < D/2.8 ) =
= F(D/2.8) - F(-D/2.8) =
= F(D/2.8) - (1-F(D/2.8))& =
= 2 * F(D/2.8) – 1 = 0.9
& F(D/2.8) = 1.9/2 = 0.95
& D/2.8 = 1.644854
D = 4.6
Hence the heights being in the middle 90% of all 20-25 years old females should be in the following interval:
& [ 64.1-4.6, 64.1+4.6 ]& =& [59.5,& 68.7]
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