Answer on Statistics and Probability Question for Jasmine
so, step 1 is to check value of student's coefficient for alpha=1-0.9=0.1 and
degree of freedom = 423-1 = 422.
In tables you will find that it is approximately = 1.65
Next you have to divide your standard deviation by the square root of your
that is 27/sqrt(423) = 1.31
now multiply them
1.33*1.65 = 4.851
So your 90% confidence interval is
84+-4.851/2 = 84+- 2.4
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