57 424
Assignments Done
Successfully Done
In February 2018
Your physics homework can be a real challenge, and the due date can be really close — feel free to use our assistance and get the desired result.
Be sure that math assignments completed by our experts will be error-free and done according to your instructions specified in the submitted order form.
Our experts will gladly share their knowledge and help you with programming homework. Keep up with the world’s newest programming trends.

Answer on Statistics and Probability Question for Tim

Question #1737
1000 black beans in a a jar, plus 1 green bean. If 999 people draw beans from the jar, what is the probability of each one drawing the green bean? Need the answer and the equation that leads to the answer, please.
Expert's answer
1. 1000 black beans, 1 green bean.
Probability for 1st man men to get black bean
P1 (black) = 1000/1001.
Probability for 1st man men to get green bean
P1 (green) = 1/1001.
2. 999 black beans, 1 green bean(we suppose that beans we don’t put beans back).
Probability for 2nd man men to get black bean
P2 (black) = 999/1000
P2 (green) = P1 * 1/1000 = 1000/1001 * 1/1000

3. 998 black beans ,1 green
P3 (black) = 998/999
P3 (green) = P1 (g)P2 (g) * 1/1000 = 1000/1001 * 999/1000 * 1/999

n. For 999th man probability will be
P999 (green) = P1 (g) P2 (g)…P997 (g) P998 (g) * 1/1000 = 1000/1001 * 999/1000*…*3/4 * 2/3 * 1/2
If after a draw beans go back to jar probability for everyone will be the same and will be equal
P(black) = 1000/1001.
P(green) = 1/1001.

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!


Assignment Expert
18.11.2014 10:30

Dear doubt.
Thank you for your question. In this experiment the output of a previous trial is very important, because if a person picks out a green bean, then probability, that other person will take out a green bean, equals zero. We use probability of intersection of events and conditional probability: P(C and D)=P(C)*P(D/C), where P(C)=P1, P(D/C)=1/1000.

17.11.2014 13:04

if u don't mind i have a doubt
can i know why is P2 (green) = P1 * 1/1000 and not 1/1000 ??????

Leave a comment

Ask Your question