Question #17337

A random sample of 50 four-year olds attending day care centers provided a yearly tuition average of $3,987 and the population standard deviation of $630. Find the 90% confidence interval of the true mean.

Expert's answer

x-bar = 3648

standard error = E = 1.645 * [630/sqrt(50)]= 146.56

CI: x-bar - E < mu < x-bar + E

3501.44 < mu < 3794.56

standard error = E = 1.645 * [630/sqrt(50)]= 146.56

CI: x-bar - E < mu < x-bar + E

3501.44 < mu < 3794.56

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