Answer to Question #16030 in Statistics and Probability for Vlatko
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We can choose 5 prize tickets (maybe with grand prizes) from 30 prize tickets in a C(30,5) ways and we can choose 5 prize tickets without grand prize in C(30-3,5) = C(27,5) ways. Therefore,
P(no grand prize in 5 prize tickets) = C(27,5)/C(30,5) = 115/203.
P(at least 1 grand in 5 prize) = 1 - P(no grand in 5 prize) = 1 - 115/203 = 88/203.
So, probability that he won at least one grand prize if he won 5 prizes is 88/203.
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