Answer to Question #14171 in Statistics and Probability for robert harriss
Unfortunately, the statement of your question is a bit confusing.
What do you need to be done? Please, give us the details so we could help you
There is only one variant that fits us and combintanions of 3 out of 43
=43!/(3!*40!)=12341 is all possible variants. So the odds of picing the exact
three cars are 12340:1.
Sorry ,,Let me explain myself better.. Im am looking for what the odds/probability IE: (34652 to 1) odds
are to pick the 1st ,2nd and 3rd. place car in a nascar race,, there are 43 cars running that race...