# Answer to Question #12665 in Statistics and Probability for Dan

Question #12665

There are four teams, a,b,c,d playing in a tournament. Each team must play each of the others exactly once. Therefore each team will play exactly 3 games. The winner of the tournament will be determined by whomever has the best ending record. In the event of ties, the following two tiebreakers will be used. 1 if exactly two teams have tied for the best record, ie they both went 2-1 then whoever won their head to head match-up will be declared the winner. 2 if exactly three teams have tied for the best record ie they all went 2-1 then the tournament is declared to end in a draw. there is no winner. team a has a .7 chance of beating team b, team a has a .5 chance of beating team c, team a has a .2 chance of beating team d, team b has a .4 chance of beating team c , team b has a .7 chance of beating team d, team c has a .5 chance of beating team d.

I have 7 questions using this information.

I have 7 questions using this information.

Expert's answer

Please submit your questions with all requirements as an assignment to our control panel and we'll assist you.

## Comments

## Leave a comment