Question #119626
The mean number of errors due to a bug occurring in a minute is 0.0001. What is the
probability that no error will occur in 20 minutes?
1
Expert's answer
2020-06-08T19:55:14-0400

Poisson's distribution ,


m=0.0001m = 0.0001 per minute,


Time is given 20 min no error m=0.002m = 0.002


Probability of No error,


p(r=0)=em×mrr!=e0.002=0.998p(r= 0) =\frac{e^{-m}\times m^{r}}{r!}=e^{-0.002} =0.998



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